MYSQL教程MySQL实现差集(Minus)和交集(Intersect)测试报告

 drop table t1;
 drop table t2;
create table t1(id int primary key,nickname varchar(20),playNum varchar(20));
create table t2(id int primary key,nickname varchar(20),playNum varchar(20));
insert into t1 values(1,1,10);
insert into t1 values(2,2,20);
insert into t1 values(3,3,30);
insert into t2 values(1,1,10);
insert into t2 values(2,2,200);
insert into t2 values(3,33,300);
commit;

SELECT id, nickname, playNum, COUNT(*)
 FROM (SELECT id, nickname, playNum
FROM t1
UNION ALL
SELECT id, nickname, playNum
FROM t2
) a
GROUP BY id, nickname, playNum
HAVING COUNT(*) > 1

SELECT t1.id, t1.nickname, t1.playNum
 FROM t1 LEFT JOIN t2 ON t1.id = t2.id
WHERE t1.nickname != t2.nickname
OR t1.playNum != t2.playNum;